Joseph was given the exponential expression of (x^3 y^-4)^3 to simplify. After using his exponent properties, he calculated x^9 y^-12 as his answer. Is Joseph's answer written in its simplest form?

you would need to also lose 1 point for each of the other outcomes for it to be fair.

step-by-step explanation:

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation:

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)