There is a quadrilateral PQRS in which the length of side PQ is 6b, the length of side QR is 4a+1, the length of side RS is 11b-10, and the length of side PS is 2a+9. The measure of angle PQR is (6x+13) degrees and the measure of angle PSR is (7x-5) degrees. What must m∠QPS be for PQRS to be a parallelogram?

central angle of a triangle has the same measure as its intercepted arc.

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b