Which point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)} which point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)}

ANSWER: Either or

Explanation

For a relation to be a function, it must either be a one-to-one relation or many-to-one-relation.

The above relation is one-to-many relation because 3 is mapping on to -6 and 8.

To make the above relation a function, we must remove one of the points containing 3 as first coordinate.

This will make the relation one-to-one which then becomes a function.

See attachment for diagrammatic representation.

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hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)