(3y^6 + 4) ___ (9y^12 - 12y^6 + 16) which of the following (subtraction, multiplication, addition) would result in a binomial?

Multiplication

Step-by-step explanation:

(3y^6+4)(9y^12−12y^6+16)

=(3y^6+4)(9y^12+−12y^6+16)

=(3y^6)(9y^12)+(3y^6)(−12y^6)+(3y^6)(16)+(4)(9y^12)+(4)(−12y^6)+(4)(16)

=27y^18−36y^12+48y^6+36y^12−48y^6+64

=27y^18+64

Wow sorry this was a lot.