How to evaluate higher powers of i

i^0 = 1

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

i^5 = i

i^6 = -1

i^7 = -i

i^8 = 1

i^9 = i

Step-by-step explanation:

Anything raised to 0 is 1

Anything raised to 1 is itself

I just always knew i^2 = -1

I put this rest into the calculator honestly

But if you look at the stuff from i^2, you'll notice there's a pattern (-1, -i, 1, i) and it repeats. I bet if you raise i to the 10th, 11th, 12th, and 13th power, it is going to repeat the same pattern. I hope this helps in any way.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c