In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of ∠K, to the nearest 10th of a degree.

Given:

In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°.

To find:

The value of  ∠K to the nearest 10th of a degree.

Solution:

According to the Law of Sine:

We have, In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°.

Using the Law of Sine, we get

Therefore, the measure of angle K is 74.0 degrees.