A line passes through the points (-4,-1) and (4,3). A second line passes through the points (-2,-2) and (2,6). At what point do the two lines intersect

(-2/3 , 2/3)

Step-by-step explanation:

Line 1: (-4,-1) (4,3)

m = (3 - -1) / (4 - -4) = 4/8 = 1/2

equation: (y-3)/(x-4) = 1/2          y-3 = 1/2 x - 2

y = 1/2 x + 1 (1)

Line 2: (-2,-2) (2,6)

m = (6 - -2) / (2 - -2) = 8/4 = 2

equation: (y-6)/(x-2) = 2              y-6 = 2x - 4

y = 2x + 2  ...(2)

(2)-(1): 0 = 3/2x + 1

3/2 x = -1            x = - 2/3

y = 1/2 * (-2/3) + 1 = 2/3

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

i dont get the question

step-by-step explanation: