A bag holds 11 beads 7 of the beads are red the rest are white two beads are taken at random work out the probability that one one bead of each colour is taken. You must show your working out

28/55

Step-by-step explanation:

total no of beads are 11

red beads are 7

and white beads are 4

no of ways to take 2 beads from 11 beads are 11c2

that is( 11*10)/2=55

no of ways to take 1 red bead from 7 is 7c1 that is 7

no of ways to take 1 white bead from 4 is 4c1 is that is 4

required probability is( 7*4)/55=28/55

this question has already been answered on someone else's account so know this answer is 100% correct

hope that helped :)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

only 10/60 isn't equivalent

hope this : )