The binary value of the ASCII letter "c" is 0110 0011. Using the handy chart that we learned in the lesson, convert this number to its decimal value. You'll need to use some math for this question 128,64,32,16,8,4,2

Decimal value is 99

Step-by-step explanation:

To convert 01100011 to decimal, we use the zero index method by counting from the last digit

0 = 7

1 = 6

1 = 5

0 = 4

0 = 3

0 = 2

1 = 1

1 = 0

Then we proceed by multiplying the binary digits by 2 and raising them to the power of their zero-index equivalent

(0*2^7) + (1*2^6) + (1*2^5) + (0*2^4) + (0*2^3) + (0*2^2) + (1*2^1) + (1*2^0)

  =(0*128) + (1*64) + (1*32) + (0*16) + (0*8) + (0*4) + (1*2) + (1*1)

      =0 + 64 + 32 + 0 + 0 + 0 + 2 + 1

         = 64 + 32 +3

             =99

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.