A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y=-162? + 1362 +57

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

1,2,4,5,10,11,20,22,44,55,110,220

answer: graphs are something you write or draw and equations are math problems

answer: ⇒ d. (7.3)(8.52)=62.19

step-by-step explanation:

product it's going to be multiply by the numbers, fractions, factors, and multiples.

1. (29.5)(1.7)=50.15

2. (13.2)(4.5)= 59.4

3. (4.67)(9.8)= 45.76

4. (7.3)(8.52)= 62.19

hope this !

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