Find the equation of a line which has: slope of -2 and
crosses the y-axis at 5

in slope-intercept form

y = -2x + 5

Step-by-step explanation:

Recall that slope-intercept form is y = mx + b where m is the slope and b is the y intercept

In this case our slope is m = -2

and, line crosses y-axis at 5 which is b = 5

thus, y = -2x + 5

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb