Assume that x = x(t) and y = y(t). Let y = x^2 + 6 and
dx/dt=4 when x=1
Find dy/dt when x = 1

= 8

Step-by-step explanation:

Given:

x = x(t) and y = y(t)

Let y = x² + 6

By differentiating the given equation with respect to t,

Since, when x = 1

[By substituting the values of and x = 1]

= 8

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,