(1). There are always 4 bars of chocolates, left when box of chocolates shared
equally among 8, 10, or 12 children.
Find the smallest number of chocolates
in the box,

The smallest number of chocolates in the box is 124.

Step-by-step explanation:

There are always 4 bars of chocolates left in the box when they are share equally among 8, 10, or 12 children.

This means that the smallest number of chocolates in the box is 4 added to the least common multiple of 8, 10 and 12.

LCM(8,10,12).

We factore them by prime factors until all are 1. So

8 - 10 - 12|2

4 - 5 - 6|2

2 - 5 - 3|2

1 - 5 - 3|3

1 - 5 - 1|5

1 - 1 - 1

So

lcm(8,10,12) = 2*2*2*3*5 = 8*15 = 120

Adding 4: 120 + 4 = 124

The smallest number of chocolates in the box is 124.

i need the table so i can see

step-by-step explanation:

1

step-by-step explanation:

it's the only multiple of both and the least