Recall that an American Roulette wheel has 38 possible outcomes, 18 black, 18 red and 2 green. The numbers go from 1 to 36, and the green outcomes are numbered 0 and 00. Someone places 10 bets on "1st 12", that is, that person wins if the outcome is any number between 1 and 12, included. 1. (2pts) What is the probability of losing a ’1st 12’ bet on a single spin? 2. (3pts) What is the probability of winning 7 out of the 10 total bets?

American Roulette

1. The probability of losing a  ’1st 12’ bet on a single spin is:

= 0.67

2. The probability of winning 7 out of the 10 total bets is:

= 0.23

Step-by-step explanation:

Possible outcomes in an American Roulette wheel = 38

Make-up of the outcomes = 18 black, 18 red and 2 green

Green outcomes are numbered 0 and 00

Number of wins for this person = 12

Probability of winning = 0.33  (12/36)

Number of possible losses for this person = 24

Probability of losing = 0.67 (24/36)

1. The probability of losing a  '1st 12' bet on a single spin is:

= (36 - 12)/36

= 0.67

2. The probability of winning 7 out of the 10 total bets is:

Probability of winning = 12/36 * 7/10

= 0.23

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

sine

step-by-step explanation: