Debra is buying prizes for a game at her school's fundraiser. The game has three levels of prizes, and she has already bought the second and third prizes. She wants the first prize to be nice enough to attract people to the game. The game's manufacturer has supplied her with the probabilities of winning first, second, and third prizes. Tickets cost $3 each, and she wants the school to profit an average of $1 per ticket. How much should she spend on each first prize

$9.19

Step-by-step explanation:

We are given that

Cost of each ticket=$3

Average profit per ticket=$1

Expect gain for ticket purchaser must be -$1

Let x be the cost of first prize

Probability of first prize=0.15

Probability of second prize=0.30

Probability of third prize=0.45

Cost of second prize=$1.15

Cost of third prize=$0.74

Total probability=0.15+0.30+0.45=0.9

Probability of winning =0.9

Probability of losing=1-0.9=0.1

According to question

Hence, she spend money on each first prize=$9.19

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23