Sheldon wants to feed his strawberry plants 2 more times and his tomato plants two more times. He will use the same amounts of plant food as before . How much plant food will he need? Does he have enough left to do so/ explain your answer using words or numbers

He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

Step-by-step explanation:

On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.

Total food bought = 4 1/2 kg

Strawberry feed = 1 2/3 kg

Tomato feed = 1/4 kg

Total food used on Sunday = Strawberry + tomato

= 1 2/3 + 1/4

= 5/3 + 1/4

= (20+3)/12

= 23/12 kg

Total food remaining after Sunday = Total food bought - used food

= 4 1/2kg - 23/12kg

= 9/2 - 23/12

= (54-23)/12

= 31/12 kg

= 2 7/12 kg

Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.

Strawberry = 2 × 1 2/3kg

= 2 × 5/3

= 10/3 kg

Tomato = 1 × 1/4kg

= 1/4 kg

Total food needed to feed strawberry two more times and tomato 1 more time

= 10/3 kg + 1/4 kg

= (40+3)/12

= 43/12 kg

= 3 7/12 kg

He will need 3 7/12 kg of food

He has 2 7/12 kg of food left

Therefore, he doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier