The area (A) of a rectangle varies jointly as the length (l) and the width (w), and whose A = 60 sq. cm when l = 4 cm and w = 3 cm. What is the area of rectangle if the length is 6 cm and whose width is 3 cm?

The area is 90 sq. cm

Step-by-step explanation:

Given

The variation can be represented as:

Area = 60, when l = 4 and w = 3

Required

Find Area, when l = 6 and w = 3

Represent the variation as an equation

Where k is the constant of variation.

Substitute 60 for A, 4 for l and 3 for w

Make k the subject

To get the value of Area when l = 6 and w = 3.

Substitute 5 for k, 6 for l and 3 for w in

The area is 90 sq. cm

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

abde or 1,2,4, 5 is the answer

step-by-step explanation: