Triangle QRS has the angle measures shown. What is the measure of the obtuse angle?

m2Q=(1x)

mZR= (3x)

m25 = (6x)

O 18

54

108

© 216

108 degrees

Step-by-step explanation:

Given the following angle measures in triangle QRS

m<Q = 1x

m<R = 3x

m<S = 6x

Note that the largest angle is the obtuse angle since they are always greater than 90 and less than 180 degrees

The sum of angle in a triangle is 180 degrees

m<Q + m<R + m<S = 180

1x + 3x + 6x = 180

10x = 180

x = 180/10

x = 18

The obtuse angle is 6x

Measure of the obtuse angle = 6x

Measure of the obtuse angle = 6(18)

Measure of the obtuse angle = 108 degrees

Hence the measure of the obtuse angle is 108 degrees

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

srry idk

step-by-step explanation: