Assume that trees are subjected to different levels of carbon dioxide atmosphere with 6% of the trees in a minimal growth condition at 360 parts per million (ppm), 13% at 450 ppm (slow growth), 46% at 560 ppm (moderate growth), and 35% at 640 ppm (rapid growth). What is the mean and standard deviation of the carbon dioxide atmosphere (in ppm) for these trees

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.

the answer is 40.

proof:

to complete this square you have to rotate about the origin 270 degrees clockwise.