The length of a rectangle is nine inches less than twice the width if the perimeter of the rectangle is 84 inches find the dimensions of the rectangle

Dimensions of the rectangle are 25 inches × 17 inches.

Step-by-step explanation:

Let the length of the rectangle = l inches and width = w inches

The length of the rectangle is 9 inches less than twice the width.

Therefore, l = (2w - 9)

Perimeter of the rectangle is = 84 inches

And perimeter of the rectangle = 2(Length + width)

                                                    = 2(l + w)

                                                    = 2[(2w - 9) + w]

                                                    = 2[3w - 9]

Now 84 = 2{3w - 9)

3w - 9 =

3w - 9 = 42

3w = 42 + 9

3w = 51

w =

w = 17 inches

Since l = 2w - 9

l = 2×17 - 9

 = 34 - 9

 = 25 inches

Therefore, dimensions of the rectangle are 25 inches × 17 inches.

what is the question here

step-by-step explanation:

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8