A baker makes apple tarts and apple pies each day. Each tart, t, requires 1 apple, and peach pie, p, requires 8 apples. The baker receives a shipment of 184 apples every day. If the baker makes no more than 40 tarts per day, which system of inequalities can be used to find the possible number of pies and tarts the baker can make? t ≤ 40
p ≤ 184
t ≤ 40
8p ≤ 184
t ≤ 40
p + 8t ≤ 184
t ≤ 40
8p + t ≤ 184
the answer is D is the answer

i think 8p+tLess equal to 184

Step-by-step explanation:

well, 40 tarts each day can result in 40 tarts 40 apples. that is already 80 apples. then if you take p (peach pie) requires 8 apples, and you have 104 left.  now that you know that, you have to take 104 / 8 and you would get 13. so 13 peach pies result in 104 apples used.

that would mean:

8p < 184

p + 8t < 184

and more but i can add them if you need them

can someone answer this question plz

step-by-step explanation:

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.