5 What is the solution for the equation 363 -262-5 BP-2
-26-5-622?
b= -4 and b=0
b = -4
b = 0 and b = 4
Ob=4

idk

step-by-step explanation:

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< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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