The area of a rectangle is 48 square centimeters the length of the rectangle is 8 centimeters longer than the width? which equation models this situation?

a. w+8=48
b. w+8w=48
c. w(w+)=48
d.8w=48

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

the answer is 8/21

hope this

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

answer is c

step-by-step explanation:

81/12=324/x

x=48