Solve
-2cos(x)-2sin^2(x)+2cos^2(x) = 0, π ≤x ≤π

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

only 10/60 isn't equivalent

hope this : )