Jay had 6 times as much money as Kay. Then Jay gave Kay $33. Jay now has twice as much money as Kay. How much did they each start with?

Jay started with $148.5 and Kay with $24.75.

Step-by-step explanation:

With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:

J=6K, where

J is the money Jay had

K is the money Kay had

Also, you know that  Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:

J-33=2(K+33)

Now, you can replace J=6K in this equation and solve for K:

6K-33=2K+66

6K-2K=66+33

4K=66

K=24.75

Then, you can replace the value of K in J=6K:

J=6*24.75

J=148.5

According to this, the answer is that Jay started with $148.5 and Kay with $24.75.

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step-by-step explanation:

9-15%

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)