Two joggers set out at the same time from their homes 24 miles apart. They agree to meet at a point somewhere in between in an hour and a half. If the rate of one is 6 mph faster than the rate of other,
find the rate of each.

9514 1404 393

  5 mph, 11 mph

Step-by-step explanation:

Together, they cover 24 miles in 1.5 hours, so their total rate of speed is ...

  (24 mi)/(1.5 h) = 16 mi/h

If s is the rate of the slower jogger, then s+6 is the rate of the faster one. Their total speed is ...

  s + (s+6) = 16

  2s = 10 . . . . . . . subtract 6

  s = 5 . . . . . . . . . divide by 2

  s+6 = 11

The rates of the joggers are 5 mph and 11 mph.

168

step-by-step explanation:

i am pretty sure that the answer is 168

if you was gonna solve for a, a is a   < -12