What is an equation of the line that passes through the points (6,8) and (-3,2)?

1. Use the slope formula
(6, 8) where x1 = 6 and y1 = 8
(-3, 2) where x2 = -3 and y2 = 2
Slope (m) = (y2-y1) / (x2-x1)
= (2-8) / (-3-6)
= -6 / -9
= 2/3

2. Use point-slope formula
y-y1=m(x-x1)
y-8=2/3(x-6)
y-8=2/3x -4

y = 2/3x + 4 :)

Where’s the problems ? ?