What is the probability of drawing two pink marbles if the first one is NOT placed back
into the bag before the second draw?

If this is the one that I am doing also then this is the correct answer because I just got this done.

Step-by-step explanation:

First find out the total number of marbles:

In this case it is 10

Keep this number in mind as it will be the denominator

The probability of getting a pink the first time would be: 3/10

Since it is replacement, there would still be 3 pink marbles for the second draw so this fraction would also be 3/10

You would need to multiply these results together to get the final result:

3/10 x 3/10

Doing this would give you an answer of: 9/100

Hope This Helps You!

Step-by-step explanation:

ya what he said

d is correct

step-by-step explanation:

dont't really have enough info here but its likely

sss for the three sides being congruent ( its stands for side side side)

or

sas   for side angle side.   so a side is congruent and and angle and a side