Find the y-intercept of a line parallel to 8x – 2y = 12 and passes through the point (5, 3).

-17

Step-by-step explanation:

8x -2y= 12

Divide the whole equation by 2:

4x -y= 6

Rewrite the equation into the slope-intercept form (y=mx+c, where m is the gradient while c is the y-intercept).

-y= -4x +6

y= 4x -6

Thus, gradient of given line= 4.

Since parallel lines have the same gradient, gradient of line= 4.

y= 4x +c

To find the y-intercept of the lone, substitute a pair of coordinates.

When x=5, y=3,

3= 4(5) +c

3= 20 +c

c= 3 -20

c= -17

Thus, the y-intercept of the line is -17.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10