The consecutive monthly flows into and out a reservoir in a given year are the following, in relative units: Month J F M A M J J A S O N D Inflow 3 4 5 3 4 10 28 17 7 6 3 2 Outflow 7 8 7 11 6 8 21 12 5 4 5 9 The reservoir contains 50 units at the beginning of the year. How many units of water are in the reservoir at the middle of August

41.5 units

Step-by-step explanation:

Given the data :

Month : J F M A M J J A S O N D

Inflow : 3 4 5 3 4 10 28 17 7 6 3 2

Outflow : 7 8 7 11 6 8 21 12 5 4 5 9

The unit of water in reservoir at the middle of August :

Initial unit = Unit of water at the start of the year = 50

Middle of August :

Inflow = 17 /2 = 8.5

Outflow = 12 /2 = 6

Unit of water at the middle of August :

Initial unit + Inflow - Outflow

Inflow till mid-August = (3+4+5+3+4+10+28+8.5) = 65.5

Outflow till mid-August = (7+8+7+11+6+8+21+6) = 74

50 + 65.5 - 74 = 41.5

87%

step-by-step explanation:

apex answer

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )