(20 pts) In a digital communication system, messages are encoded into the binary symbols 0 and 1. Because of noise in the system, incorrect symbols are sometimes received. Suppose that the probability of a 0 being transmitted is 0.5. Further suppose that the probability of a transmitted 0 being received as a 1 is 0.05 and the probability of a transmitted 1 being received as a 0 is 0.08. Find the probability that it was 1 that was transmitted given that a 1 was received.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

step-by-step explanation:

what does 'mandy have ben 780 bottle caps. ' mean?

$15.40 per mile

step-by-step explanation:

you have to round up to 4 because 6 is over 5 so you have to round the 3 up to 4

6 adults and 9 children went.

a + c = 15

12a + 9c = 153

12(6) + 9(9) = 153

72 + 81 = 153