For each sequence, find the first 4 terms and the 10th term.
a) 3n + 4
b) 4n-5

see explanation

Step-by-step explanation:

To find the first 4 terms substitute n = 1, 2, 3, 4 into the formula, that is

(a)

a₁ = 3(1) + 4 = 3 + 4 = 7

a₂ = 3(2) + 4 = 6 + 4 = 10

a₃ = 3(3) + 4 = 9 + 4 = 13

a₄ = 3(4) + 4 = 12 + 4 = 16

Similarly substitute n = 10 for tenth term

a₁₀ = 3(10) + 4 = 30 + 4 = 34

(b)

a₁ = 4(1) - 5 = 4 - 5 = - 1

a₂ = 4(2) - 5 = 8 - 5 = 3

a₃ = 4(3) - 5 = 12 - 5 = 7

a₄ = 4(4) - 5 = 16 - 5 = 11, and

a₁₀ = 4(10) - 5 = 40 - 5 = 35

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.

i think the answer is true

step-by-step explanation: