Solve for x? please help

x =

Step-by-step explanation:

The 2 right triangles and the outer right triangle are similar, then ratios of corresponding sides are equal, that is

= ( cross- multiply )

x² = 10 ( take the square root of both sides )

x =

√10

Step-by-step explanation:

taking the smallest triangle;

y as the hypotenuse, x as the adjacent side, 2 as the opposite side

then: y²=x²+2²

x²=y²-2²= y²-4

taking the other triangle;

z as the hypotenuse, x as the adjacent side, 5 as the opposite side

then: z²=x²+5²

x²=z²-5² = z²-25

take both equations,

x²= y²-4

x²= z²-25

y²-4= z²-25

y²= z²-25+4 = z²-21

taking the biggest triangle (whole triangle);

(5+2)= 7 as the hypotenuse, z as the adjacent side, y as the opposite side

then; 7²=z²+y²

z²+y²=7² =49

but y²= z²-21;

z²+y² =49

z²+ z²-21 =49

2z²-21=49

2z²=49+21= 70

z²= 70/2 = 35

take x²= z²-25

x²= 35-25 = 10

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180