A frame around a family portrait has a perimeter of 94 inches. The length of the frame is 7 inches less than twice the width. Find the length and width of the frame.

Step-by-step explanation:

Let l be the length and w be the width of the frame.

We have 2(l + w) = 94 and l = 2w - 7.

Therefore 2[(2w - 7) + w] = 94.

=> 3w - 7 = 47

=> 3w = 54

=> w = 18

l = 2(18) - 7 = 36 - 7 = 29

Hence the length of the frame is 29in and the width of the frame is 18in.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.