An investor has an account with stock from two different companies. Last year, her stock in Company A was worth $800 and her stock in Company B was worth $6180.
The stock in Company A has decreased 1% since last year and the stock in Company B
has decreased 5%. What was the total percentage decrease in the investor's stock
account? Round your answer to the nearest tenth (if necessary).

4.5%

Step-by-step explanation:

800(1-0.01)=\color{green}{792}

800(1−0.01)=792

6180(1-0.05)=\color{blue}{5871}

6180(1−0.05)=5871

Last YearThis Year

Stock A800792

Stock B61805871

Total69806663

\text{Find overall decrease:}

Find overall decrease:

6980(1-r)=6663

6980(1−r)=6663

\frac{6980(1-r)}{6980}=\frac{6663}{6980}

6980

6980(1−r)

=

6980

6663

1-r=0.954585

1−r=0.954585

-r=-0.045415

−r=−0.045415

Subtract 1

r=0.045415

r=0.045415

Divide by -1

\text{Final }4.5\%

Final 4.5%

Multiply by 100 and round to nearest 10th

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.