PLEASE HELP ME!! let g be the function given by g (x) = 3x^4 - 8x^3. At what value of x on the closed interval [ -2,2 ] does g have an absolute maximum

The value of x on the closed interval [ -2,2 ] that g has an absolute maximum is 0

Given the function

The function is at a maximum at g'(x) = 0

Differentiating the function given:

Substitute x = 0 and x = 2 into the function;

g(0) = 3(0)^3 - 8(0)^3

g(0) = 0

Since the range of the function is least at x = 0, hence the value of x on the closed interval [ -2,2 ] that g has an absolute maximum is 0

Learn more function here: link

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204