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Mathematics, 04.02.2021 23:10 daniel9299

Han found a way to compute complicated expressions more easily. Since 2 β‹… 5 = 10, he looks for pairings of 2s and 5s that he knows equal 10. For example, 3 β‹… 24 β‹… 55 = 3 β‹… 24 β‹… 54 β‹… 5 = (3 β‹… 5) β‹… (2 β‹… 5)4 = 15 β‹… 104 = 150,000. PLEASE HELP ME

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Han found a way to compute complicated expressions more easily. Since 2 β‹… 5 = 10, he looks for pairi...
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