Find the perimeter of a rectangle with sides 3x + 6 and -2x -8

2x - 4

Step-by-step explanation:

2(3x + 6) = 6x + 12

2(-2x - 8) = -4x -16

6x + 12 - 4x - 16 = 2x - 4

The perimeter of a rectangle with sides 3x + 6 and -2x - 8 will be:

Step-by-step explanation:

We know that the perimeter of a rectangle of length 'l' and width 'w' is given by the formula

Given the sides of a rectangle

As the opposite sides of a rectangle are congruent.

Therefore, we conclude that the Perimeter of a rectangle can be determined using the formula

Therefore, the perimeter of a rectangle with sides 3x + 6 and -2x - 8 will be:

question

given the diagram below, what is md?

the sum of the interior angles is 360°

take away from 360 the sum of the knows angles and you will have the angle d.

360 - 108 - 108 - 72 = 72°

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3