This figure consists of a rectangle and semicircle What is the area of this figure?
Use 3.14 for T.
Enter your answer as a decimal in the box.

Step-by-step explanation:

Area of rectangle:

= Length * Width

Where length = 4, Width = 6

= 4 * 6

= 24 cm²

Area of semi-circle:

Diameter = 6 cm

Radius = D/2 = 6/2 = 3 cm

Area = πr² / 2

Area = (3.14)(3)²/2

Area = (3.14)(9) / 2

Area = 28.3 / 2

Area = 14.1 cm²

Area of the whole figure:

= Area of the rectangle + Area of the semi-circle

= 24 + 14.1

= 38.1 cm²

Hope this helped!

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length