If f(x)=x2−1; x0=−1 (a) Find a formula for the slope of the tangent line to the graph of function at a general point x=x0
(b) Use the formula obtained in part (a) to find the slope of the tangent line for the given value of x0.

a

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96