Which shows this equation in standard form?

7 – 3(x – y) = 5x + 2

3x – 8y = 5

8x + 3y = 5

8x – 3y = 5

8x – 3y = –5

7 - 3(x - y) = 5x + 2 the first step...is to distribute the -3 into the parenthesismultiply the -3 by each term in the parenthesis...so -3 times x = -3x and -3 times -y = 3y so now we have 7 - 3x + 3y = 5x + 2 Nowwe have 2 different 'x' numbers...we can combine them to just make 1... add 3x to both sides of the equation...so 7 - 3x + 3y = 5x + 2 +3x +3x 7 + 3y = 8x + 2 Now...we can also combine those constant numbers as well...try subtracting 2 from both sides of the equation... 7 + 3y = 8x + 2 -2 -2 5 + 3y = 8x NOW we want both the variables on 1 side of the equation...so subtract 3y from both sides 5 + 3y = 8x - 3y -3y 5 = 8x - 3y or rewritten as 8x - 3y = 5
does it help?

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