wo straight lines have equations y = p x + 4 y = p x + 4 and p y = q x − 7 p y = q x − 7 , where p p and q q are constants. The two lines meet at the point ( 3 , 1 ) ( 3 , 1 ) . What is the value of q q ?

SOLUTION

GIVEN:  

Two straight lines have equations y=px+4 and py=qx−7, where p and q are constants.

The two lines meet at the point (3,1)

TO DETERMINE

The value of q

EVALUATION

Here the given equation of the lines are

Now the two lines meet at the point (3,1)

Since equation (1) passes through the point (3,1)

Again Equation (2) passes through the point (3,1)

FINAL ANSWER

Hence the required value of q = 2

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3