What is the equation of the horizontal line that contains the point (3,−8)?

The equation of the horizontal line that contains the point (3,−8) will be:

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

We need to determine the equation of the horizontal line that contains the point (3, −8).

We know that the slope of a horizontal line m = 0

Thus, in our case:

now substituting m = 0 and the point (3, -8) in the slope-intercept form of the line equation to determine the y-intercept

y = mx+b

-8 = 0(3) + b

-8 = 0 + b

b = -8

Thus, the y-intercept b = -8

now substituting m = 0 and b = -8  in the slope-intercept form of the line equation

y = mx+b

y = 0(x) + (-8)

y = 0 - 8

y = -8

Therefore, the equation of the horizontal line that contains the point (3,−8) will be:

Please also check the attached graph below.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

it is not that hard all u have to do is plot the graph

step-by-step explanation: