a smartphone has a screen that has a width of x and a height that is 1.8 times the width. the outer dimensions of the phone are increased by 1 centimeter in the width and 3 centimeters in the length. write and expression for the portion of the phone t ha t is not occupied by the screen. assume that the phone is rectangular

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

okay wait before i answer, is this for your points on a graph?

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

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