A pizzeria has two different types of crust, 3 types of cheese and 4 toppings. A personal pizza can only have one type of cheese and one topping. What is the probability of choosing a thin crust with parmesan cheese and pepperoni?

1/24

Step-by-step explanation:

So let's first find the total number of ways the pizza can be made.

2 types of crust

3 types of cheese

4 toppings

So if we choose crust 1, we have 3 options for cheese. For each of these options, we have 4 options for toppings. 4 x 3 will give us the number of topping-cheese combinations available, and likewise, we can apply this to the two crusts, getting 4 x 3 x 2, or 24.

Next, we will find the probability of choosing a thin crust with parmesan cheese and pepperoni. That's 1 crust, 1 cheese, and 1 topping, giving us 1/24 as this is a single combination.

(Probability of event)/(All possible events)

1/24

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )