Let U = {q, r, s, t, u, V, W, x, y, z} A = {q, s, u, w, y}
B = {q, s, y, z}
C ={v, w, x, y, z).
List the elements in the set (B'U C) U A'

B'=U-B={q, r, s, t, u, V, W, x, y, z}-{q, s, y, z}={r,t, u, V, W, x, y}

A'=U-A={q, r, s, t, u, V, W, x, y, z}-{q, s, u, w, y}={r,t,v,w,x,z}

B'UC={r,t, u, V,W, x, y}U{v, w, x, y, z).={{r,t, u, V,W, x, y,z}

Step-by-step explanation:

(B'U C) U A'={{r,t, u, V,W, x,y,z}U{r,t,v,w,x,z}={{r,t, u, V,W, x,y,z}

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph