The distance traveled by a snowball thrown straight down from the top of a bluff can be calculated with the equation d=ut+12gt2, where d is the distance traveled in meters, u is the initial velocity in meters per second, t is the time in seconds, and g is the acceleration due to gravity, which is 9.8ms2. If the snowball traveled 200 meters in 5 seconds, what was its initial velocity?

15.5 m/s

Step-by-step explanation:

Using the equation, d = ut+1/2gt² where all the variables have meaning as given above, making u subject of the formula, we have

d = ut+1/2gt²

d - 1/2gt² = ut

d/t - 1/2gt²/t = u

u = d/t - 1/2gt

Since d = 200 m, t = 5 s and g = 9.8m/s², substituting the values of the variables into the equation, we have

u = d/t - 1/2gt

u = 200 m/5 s - 1/2 ×  9.8m/s² × 5 s

u = 40 m/s - 49 m/s ÷ 2

u = 40 m/s - 24.5 m/s

u = 15.5 m/s

So, the initial speed of the snowball is 15.5 m/s

1/4 because there is 4 grades.

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5