Will mark brainliest! Parallelogram ABCD has diagonals AC and DB that intersect at P. If AP=8x−56, PC=24, PB=36, PD=4y+20, AB=4x+3y, and BC=5x−4y, find the perimeter of this parallelogram. Show your work

192= PERIMETER

Step-by-step explanation:

x=10 and y=4

24=8x-56

36=4y+20

AB=52

BC=44

44+44+52+52= 192

172

Step-by-step explanation:

8x-56=24                           4y+20=36

    +56    +56                         -20     -20

8x=80                                    4y=16

/8     /8                                     /4    /4

x=10                                             y=4

4x+3y                                         5x-4y=34

(4 x 10)+(3 x 4)=52                     (5 x 10)-(4 x 4)=34

2(a+b)    

2(34+52)  =  172

is this part of a question or something

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!