A line passes through the point (3,1) and has a slope of 2.

what is the y-intercept?

-5

Step-by-step explanation:

First, we can plug all the given values into the equation y=mx+b. This is called slope-intercept form. m is the slope and b is the y-intercept. To find the y-intercept, we solve for b.

y=mx+b

1=2(3)+b

1=6+b

Subtract both sides by 6

1-6=6+b-6

-5=b

Therefore, the y-intercept is -5.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2