I need answers quickly . Can someone explain how to find an nth term of a quadratic sequence? Not gcse level or using anything complicated, i'm really new to the topic. Thanks.

Suppose you are choosing a 6-digit personal access code. this code is made up of 4 digits chosen from 1 to 9, followed by 2 letters chosen from a to z. any of these digits or letters can be repeated. find the total number of personal access codes that can be formed. 492,804 341,172 39,917,124 4,435,236